pls solve tomorrow I have exams don't ignore using identity
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b²( 8 a+7 c ) ( 8 a + 7 c) is the answer
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64a²b²-49c²b²
=> (8ab)²-(7cb)² {a²-b²}
=> (8ab+7cb)(8ab-7cb)
=> b(8a+7c)(8a-7c){b is common in both}
Hope this helps you
Have a great day
And all the best for your exam
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