Question

pls solve very very urgent with written picture​

Answer 1

Answer:

Common Difference => 3

Step-by-step explanation:

=====================================

See The Attachment My Friend....

=====================================

Answer 2

QuestioN :

In an A.P the first term is - 4 and the last term is 29. If the sum of all its term is 150, Find the Common difference.

AnsWer :

D = 3.

GiveN :

• Sum of all term is 150.
• First term - 4.
• Last term ( l ) 29

SolutioN :

Let,

• First term " a "
• Common difference " d "
• Last term " l "

We have, Sum of nth term.

$\tt \dagger \: \: \: \: \: S_n = \frac{n}{2} ( 2a (n - 1)d)$

$\tt : \implies \: \: \: \: \: S_n = \frac{n}{2} ( a + a_n)$

• an is last term ( l ).

$\tt \dagger \: \: \: \: \: S_n = \frac{n}{2} ( a + l )$

$\rule{90}2$

A/Q,

$\tt : \implies150 = \frac{n}{2} ( - 4 + 29)$

$\tt : \implies150 = \dfrac{n}{2} \times 25$

$\tt : \implies30 = 25n.$

$\tt : \implies n = \dfrac{300}{25}$

$\tt : \implies n = 12.$

We have, Total 12 term.

$\tt \dagger \: \: \: \: \: a_n = a + (n - 1 )d.$

• an = ( l )

$\tt : \implies 29 = - 4+(12 - 1)d$

$\tt : \implies 29 + 4 = 11d$

$\tt : \implies 33 = 11d$

$\tt : \implies d = \dfrac{33}{11}$

$\tt : \implies d = 3.$

Therefore, the value of D = 3.