Question

pls solve with steps.pls pls pls maths algebra 9th​

Answer 1

Answer:

a3+b3+c3-3abc = (a+b+c)(a2+b2+c2-ab-bc-ca)

Step-by-step explanation:

• (a+b+c)^2= a^2+b^2+c^2+2(ab+BC+ca)
• 256=90+2(ab+bc+ca)
• Therefore ab+bc+CA=83
• substituting in answer we get
• required result=16×(90-83)=112

Hope it helps you

Answer 2

Answer:

given,a+b+c=16

a^2+b^2+c^2=90

$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)$

256=90+2(ab+bc+ca)

166=2(ab+bc+ca)

166/2=(ab+bc+ca)

(ab+bc+ca)=83

$a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))$

                               =(16)(90-83)

                               =16(7)

                               =112