Question

pls solve x and y chapter 3 class 10th rs agrawal pls give answer fast pls​ exercise 3b​

Answer 1

$\huge\bf\red{Given\::}$

• 4x - 3y = 8

• 6x - y = $\dfrac{29}{3}$

$\huge\bf\blue{Need\:To\:Find\::}$

• values of x and y

$\huge\bf\purple{Solution\::}$

• 4x - 3y = 8_______①
• 6x - y = $\dfrac{29}{3}$_______②

Let us multiply eq② with 3

➙ 6x - y = $\dfrac{29}{3}$ × 3

18x - 3y = 29

4x - 3y = 8

-     +     -

----------------

14x = 21

----------------

➙ x = $\dfrac{21}{14}$

➙ x = $\bf\dfrac{3}{2}$

Putting x value in eq①

➙ 4 × $\dfrac{3}{2}$ - 3y = 8

➙ 6 - 8 = 3y

➙ -2 = 3y

➙ y = $\bf\dfrac{-2}{3}$

Hence

• $\bf\orange{x \ = \ \dfrac{3}{2} }$

• $\bf\orange{y \ = \ \dfrac{-2}{3}}$

Answer 2

SOLUTION:-

Given

▪︎ 4x-3y=8

▪︎ 6x-y=29/3

To find

Value of x and y

Explanation

▪︎ 4x-3y=8___________(1)

▪︎ 6x-y=29/3___________(2)

Firstly, Take eq 2

▪︎6x-y=29/3

= 6x-y-29/3=0

Take LCM

$\frac{18x - 3y - 29}{3} = 0 \\ \\ =$

18x-3y=29_______(3)

On Subtracting eq1 form 3

18x - 3y = 29

4x - 3y = 8

- + -

__________

14x = 21

x=21/14

x= 3/2

Putting value of x in eq 3

▪︎ 18x-3y=29

= 18×3/2-3y=29

= 27-3y=29

= -3y=29-27

= -3y= 2

= y= -2/3

So the value of x = 3/2 and y= -2/3