pls solvled it i can't solved it so plss brainmasters solved this question
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mass of Na2SO4 = 142
so the compound contains nearly 44 percent Na2SO4
1percent Na2sO4 Mass= 142/44 = 3.22
H20 = 56 percent
H20 mass = 3.22 ×56 = 180.22
Moles of H20 = 180.22/18= 10moles
18 is molar mass of H20
answer is D part Na2SO4. 10 H20
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THE ANSWER IS...
Molar mass of salt = (2 × 23) + 32 + (16 × 4) + x × 18 = 142 + 18x
On heating it will lose water and become anhydrous. 55.9% mass is the mass of water in Na2SO4.xH2O.
Mass by mass% = (mass / molar mass of compound) × 100
mass of water = 18x
55.9 = (18x / 142 + 18x) × 100
55.9(142 + 18x) = 1800x
7937.8 + 1006.2x = 1800x
x = 9.99
x = 10 (approx.)
So, the molecular formula of compound is Na2SO4.10H2O.
hope it is useful mate......
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