Chemistry, asked by gaytriparmar, 10 months ago

pls solvled it i can't solved it so plss brainmasters solved this question

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Answered by aaravaki2106
0

Answer:

mass of Na2SO4 = 142

so the compound contains nearly 44 percent Na2SO4

1percent Na2sO4 Mass= 142/44 = 3.22

H20 = 56 percent

H20 mass = 3.22 ×56 = 180.22

Moles of H20 = 180.22/18= 10moles

18 is molar mass of H20

answer is D part Na2SO4. 10 H20

Answered by jklm97abhithashetty
0

THE ANSWER IS...

Molar mass of salt = (2 × 23) + 32 + (16 × 4) + x × 18 = 142 + 18x

On heating it will lose water and become anhydrous. 55.9% mass is the mass of water in Na2SO4.xH2O.

Mass by mass% = (mass / molar mass of compound) × 100

mass of water = 18x

55.9 = (18x / 142 + 18x) × 100

55.9(142 + 18x) = 1800x

7937.8 + 1006.2x = 1800x

x = 9.99

x = 10 (approx.)

So, the molecular formula of compound is Na2SO4.10H2O.

hope it is useful mate......

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