Pls some one solve the attached file tmr exammmmm
Attachments:
Answers
Answered by
1
the total distance is 50m +40+20+Ad
AD=√30*30+40*40
AD=50
total distance
50+50+40+20=160
displacement=AD=50
AD=√30*30+40*40
AD=50
total distance
50+50+40+20=160
displacement=AD=50
Similar questions