Pls...somebody ans the 7th one...
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Anonymous:
120°
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Here is your answer
we know that the angle subtended by a chord at the centre of the circle is twice the angle subtended by it on the remaining part of the circle.
so, here
angle AOC=2× angleAPC
120*=2×angle APC
angle APC= 60*
Since,ABCP is a cyclic quadrilateral
so, its exterior angle is equal to its interior opposite angle
Hence,
x= angleAPC
x= 60*
HOPE IT IS USEFUL
we know that the angle subtended by a chord at the centre of the circle is twice the angle subtended by it on the remaining part of the circle.
so, here
angle AOC=2× angleAPC
120*=2×angle APC
angle APC= 60*
Since,ABCP is a cyclic quadrilateral
so, its exterior angle is equal to its interior opposite angle
Hence,
x= angleAPC
x= 60*
HOPE IT IS USEFUL
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