Question

Pls someone answer fast pls

Answer 1

option (D) is correct
hope it help you

Answer 2

$\mathsf{Given : \dfrac{16 \times 2^n^+^1 - 4 \times 2^n}{16 \times 2^n^+^2 - 2 \times 2^n^+^2}}$

$\mathsf{\implies \dfrac{16 \times 2^n^+^1 - 2^2 \times 2^n}{16 \times 2^n^+^1 \times 2 - 2 \times 2^n^+^2}}$

$\mathsf{\implies \dfrac{(16 \times 2^n^+^1 - 2^n^+^2)}{2(16 \times 2^n^+^1 - 2^n^+^2)}}$

$\mathsf{\implies \dfrac{1}{2}}$

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Laws of Exponents used to Solve the Problem :

$\heartsuit$  $\mathsf{a^m \times a^n = a^m^+^n}$

$\heartsuit$  $\mathsf{a^n = a^n^-^1 \times a^1}$