Math, asked by srijan50, 8 months ago

pls someone answer.I'll mark it as the brainliest​

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Answered by akshit1229
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Answer:

LET A BE Y

 {y}^{2}  + 4y + x = (y + 2) {}^{2}  \\  {y}^{2}  + 4y + x =  {y}^{2}  + 4 + 4y \\ x = 4

 \\  \\  {y}^{2}  + 4y + 4 = 0 \\  {y}^{2} + 2y + 2y + 4 = 0 \\ y =  - 2

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PLS MARK AS BRAINLIEST

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