Pls someone answer this fast..
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hey mate
here is ur answer
512^3-253^3-259^3
=(253+259)^3-253+259^3
=(253^3+3 *253^2*259+3*253*259^2+259^3)-253^3+259^3
=3*253^2*259+3*253*259^2
=3*253*259*(253+259),by factoring
=3*253*259*512
=3*(11*23)*(7*37)*2^9
=2^9*3*7*11*23*37.
Since 2,3,7,11,23,37 are primes ,I conclude that the given number has 6 distinct prime number's.
I hope this helps!
here is ur answer
512^3-253^3-259^3
=(253+259)^3-253+259^3
=(253^3+3 *253^2*259+3*253*259^2+259^3)-253^3+259^3
=3*253^2*259+3*253*259^2
=3*253*259*(253+259),by factoring
=3*253*259*512
=3*(11*23)*(7*37)*2^9
=2^9*3*7*11*23*37.
Since 2,3,7,11,23,37 are primes ,I conclude that the given number has 6 distinct prime number's.
I hope this helps!
Unique99:
kyu.......iplx dlt all commt koye aur bst ha yes or no
ok report karo is ko
Kroger tum
i knw u hve bst otherone dlt ths
Report this answer..
ok uhve now vst otherone
Can ya just stop @elsa
u also cheter
u cheter
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