Math, asked by sumangalikuppusamy, 9 months ago

pls someone answer this plsssss​

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Answers

Answered by GalacticCluster
7

Answer:

Option 4). 60°

ExplanaTion:

CotØ = 1/√3

→ Cot60 = 1/√3

You've to learn the numeric values from the following table:

\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 65^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0  \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $    \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ &  1 &  $ \dfrac{1}{ \sqrt{3} } $ &0 \\  \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\  \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1  \\  \cline{1 - 6}\end{tabular}}

Some extra things to remember while solving trignometrical questions:

  • Sin²Ø + Cos²Ø = 1
  • Sec²Ø - Tan²Ø = 1
  • Cosec²Ø - Cot²Ø = 1
  • SinØ = 1/CosecØ
  • CosecØ = 1/CosecØ
  • TanØ = 1/CotØ
  • CotØ = 1/TanØ
  • SecØ = 1/CosØ
  • CosØ = 1/SecØ
Answered by AKStark
0

Answer:

 \cot(60)  =  \frac{1}{ \sqrt{3} }

ANSWER WILL BE OPTION D =60°.

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