Math, asked by divithelearner04, 11 months ago

Pls someone answer this Question fast!!!!!!!!!!!!!!!!!!!!!!!!​

Attachments:

saurabhasthana: Given : Zeroes are 2/3 and -1/4

To Find: Find the polynomial

Solution:

formula of polynomial = x^{2}+(\alpha+\beta)x+\alpha\beta=0x2+(α+β)x+αβ=0

Where α = 2/3

β =  -1/4

so putting values in formula:

x^{2}+(\frac{2}{3} -\frac{1}{4} )x+(\frac{2}{3}* \frac{-1}{4})=0x2+(32​−41​)x+(32​∗4−1​)=0

x^{2}+\frac{5}{12}x+\frac{-2}{12}=0x2+125​x+12−2​=0

12x^{2}+5x-2=012x2+5x−2=0

Hence the required expression is12x^{2}+5x-2=012x2+5x−2=0

Answers

Answered by SRK1729
0

every quadratic equation is in the form

x^2-(a+b)x+ab

where a and b are zeroes!

given a =2/3 and b=-1/4

so equation is

x^2 -(2/3-1/4)x+2/3×-1/4

x^2-5x/12-1/6

= 1/12(12x^2-5x-2)..

now we have to verify

so we know already

that , a+b= 5/12

5/12=5/12

ab =-1/6

-1/6=-1/6

Answered by arthraj04
0

Alpha+beta = ,-b/a

-b/a = 2/3 (take first value)

-b/2=a/3

K=-b/2,K=a/3

b=-2K,a=3k

Alpha *beta =c/a

c/a=-1/4 (take second value)

c=-a/4

c=-3k/4 (put value of a)

Cubic equation is

ax^2+bx+c

3kx^2 -2kx-3k/4 (putting value of a b c)

K(3x^2-2x-3/4) (taking K comman)

Your quadratic equation is 3x^2-2x-3/4

Please mark it as brain list

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