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the paper is folded along its length so the perimeter of base of cylinder will be 11
2πr = 11
2×22/7 ×r = 11
r=11×7/2×22
r=7/4
volume of cylinder = πr2h
22/7×7/4×7/4×4
154/4
=38.5cm3
2πr = 11
2×22/7 ×r = 11
r=11×7/2×22
r=7/4
volume of cylinder = πr2h
22/7×7/4×7/4×4
154/4
=38.5cm3
Answered by
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Area of paper= 11×4=44 square cm.
So curve surface area=2 π r h= 2×22/7 × r ×4
So as per question, 176 r/7 = 44
or, r =44×7/176= 7/4cm
Now volume = π × r^2 ×h= π × 49/16 × 4=49π/4=12.25π cubic cm
So curve surface area=2 π r h= 2×22/7 × r ×4
So as per question, 176 r/7 = 44
or, r =44×7/176= 7/4cm
Now volume = π × r^2 ×h= π × 49/16 × 4=49π/4=12.25π cubic cm
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