Question

Pls someone can help me with this

Answer 1

Step-by-step explanation:

Let F be the midpoint of DC name BF$=h^1$ (imagine)

Let G be the midpoint of AE name BG$=h$ (given)

By using similarity of triangles

$\frac{BG}{AE} =\frac{BF}{DC}$$=\frac{h}{20} =\frac{h^1}{10}$

This implies  $h=2h^1$

As we can see in the figure clearly given that FG=36 cm

$FG=BF+BG$

$36=h+h^1$

$36=2h^1+h^1$

$36=3h^1$

$h^1=12 cm$

Therefore;   $h=24cm$

To understand the problem draw the diagram by yourself according to interpretation done here