pls someone help me out in this question....i'll give u 100 points if u ans this
Answers
Answer:
The stone will go 20.408 metres high before it begins to fall
Explanation:
Hi !
Initial velocity = u = 20 m/s
Final velocity = v = 0 [ at maximum height , v = 0 ]
Acceleration due to gravity(g) in this case , is taken as negative.
This is because , when the direction of motion of object is opposite to "g" , then value of g is taken as -ve
hence ,
g = -9.8 m/s²
Let's use the formula :-
[h = height ]
v² -u² = 2gh
0² - 20² = 2*-9.8*h
-400 = -19.6h
h = -400/-19.6
= 20.408 m [ approximately ]
The stone will go 20.408 metres high before it begins to fall
Read more on Brainly.in - https://brainly.in/question/1552849#readmore
ANSWER :
Initial velocity = u = 20 m/s
Final velocity = v = 0
(at max. height, v = 0)
Acceleration due to gravity(g) in this case , is taken as negative.
This is because , when the direction of motion of object is opposite to "g" , then value of g is taken as -ve
So, g = -9.8 m/s²
Let's use the formula :-
→ v² - u² = 2gh ( where h = height)
→ 0² - 20² = 2 x (-9.8) x h
→ -400 = -19.6h
→ h = -400/-19.6
= 20.408 m ( approx. ) ________(Ans.)
Hence, The stone will go 20.408 metres high before it begins to fall.
Hope it helps....
^___°