Question

pls someone help me out in this question....i'll give u 100 points if u ans this​

Answer 1

Answer:

The stone will go 20.408 metres high  before it begins to fall

Explanation:

Hi !

Initial velocity = u = 20 m/s 

Final velocity = v = 0              [ at maximum height , v = 0 ]

Acceleration due to gravity(g)  in this case , is taken as negative.

This is because , when the direction of motion of object is opposite to "g" , then value of g is taken as -ve

hence ,

g = -9.8 m/s²

Let's use the formula :-

[h = height ]

v² -u² = 2gh

0² - 20² = 2*-9.8*h

-400 = -19.6h

h = -400/-19.6

 = 20.408 m [ approximately ]

The stone will go 20.408 metres high  before it begins to fall

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Answer 2

ANSWER :

Initial velocity = u = 20 m/s 

Final velocity = v = 0      

(at max. height, v = 0)

Acceleration due to gravity(g)  in this case , is taken as negative.

This is because , when the direction of motion of object is opposite to "g" , then value of g is taken as -ve

So, g = -9.8 m/s²

Let's use the formula :-

→ v² - u² = 2gh ( where h = height)

→ 0² - 20² = 2 x (-9.8) x h

→ -400 = -19.6h

→ h = -400/-19.6

= 20.408 m ( approx. ) ________(Ans.)

Hence, The stone will go 20.408 metres high  before it begins to fall.

Hope it helps....

^___°