Question

pls someone help to do this no​

Answer 1

hi..here is ur answer!!

Step by Step Solution:

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Reformatting the input :

Changes made to your input should not affect the solution:

(1): "c2"   was replaced by   "c^2".  2 more similar replacement(s).

STEP

1

:

Equation at the end of step 1

 (((4•(a2))+4ab)+(b2))+32c2

STEP  

2

:

Equation at the end of step

2

:

 ((22a2 +  4ab) +  b2) +  32c2

STEP

3

:

Final result :

 4a2 + 4ab + b2 + 9c2

HOPE HELPFUL!!

❤

Answer 2

Answer:

(2a+b+3c)(2a+b-3c)

Step-by-step explanation:

$given \: expession \: is \\ 4 {a}^{2} + 4ab + {b}^{2} - 9 {c}^{2}$

it can be written as ;

$({2a})^{2} + (2)(2a)(b) + {b}^{2} - 9 {c}^{2}$

we know

$({a + b})^{2} = {a}^{2} + 2ab + {b}^{2}$

so the expression is as follows;

$({2a + b})^{2} - 9 {c}^{2}$

we also know that

${a}^{2} - {b}^{2} = (a + b)(a - b)$

so the factorisation is;

(2a+b+3c)(2a+b-3c)