Question

pls someone help to do this one​

Answer 1

bc√x^b-c × ca√x^c-a × ab√x^a-b = x^0

x^ (b-c÷bc) × x^(c-a ÷ca) × x^(a-b÷ab) = x^0

b - c c - a a - b

------ + ------- + ------- = 0

bc ca ab

a(b-c) + b(c-a) + c(a - b)

------------------------------------- = 0

abc

ab -ac + bc - ac + ac - bc

------------------------------------- = 0

abc

0

----- = 0

abc

0=0

hence prove