pls someone help to do this one
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bc√x^b-c × ca√x^c-a × ab√x^a-b = x^0
x^ (b-c÷bc) × x^(c-a ÷ca) × x^(a-b÷ab) = x^0
b - c c - a a - b
------ + ------- + ------- = 0
bc ca ab
a(b-c) + b(c-a) + c(a - b)
------------------------------------- = 0
abc
ab -ac + bc - ac + ac - bc
------------------------------------- = 0
abc
0
----- = 0
abc
0=0
hence prove
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