Pls someone tell Q24
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top 3 resistances are in parallel
hence p.d.across them is equal
2×1=4×current in 4ohm
0.5=current in 4ohm
since above 4ohm resistances are parallel hence current is same
So total current in above wire is=0.5+0.5+1=2A
You can calculate that the equivalent resistance of above branch is equal to equivalent resistance of lower branch .Hence current is same as both are in parallel
total current is =2+2=4A
the current in 12 ohm resistor is 1A (you can try)
the power drop is i^2R in 12 ohm resistor
total power drop in both is 12+12=24watt
Explanation:
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