Math, asked by muhammadhazath4231, 7 months ago

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1.uditha is employed in a private company. his first monthly salary is Rs.2500.from the beginning of the second year on wards .he receives an annual salary increment of Rs.2400per month .

a.general term ?

2.brokerage fee of three percentage is charged when a land is sold. if the land on a received 27 lakhs in rupees after the brokerage fee was paid find the price at which the land was sold?

3.what is the fraction by which 1

1  \frac{3}{4}
has to be multiplied to obtain
3 \frac{3}{4}
?

4.​

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Answers

Answered by abilashgorja
1

Answer:

ANSWER

Let the original salary be x and yearly increment be y.

After 4 years, his salary will be Rs.4500

∴x+4y=4500

⇒x=4500−4y.....(1)

After 10 years, his salary becomes 5400.

∴x+10y=5400

⇒4500−4y+10y=5400(From (1))

⇒y=150

Substituting the value of y in equation (1), we have

⇒x=4500−4×150

⇒x=4500−600=3900

Hence, his original salary was Rs.3900 and increment per year is Rs.150

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