Question

pls tell 5he anz fast​

Answer 1

$\huge \pink{ \underline{ \underline \red{\bf{Solution:}}}}$

$\bf{Given \: inequation, \: \frac{(4x - 10)}{3} ≤ \: \frac{(5x -7)}{2} }$

$\bf{2(4x - 10) \: ≤ \: 3(5x–7)}$ [On cross-multiplying

$\bf{8x–20 \: ≤ \: 15x–21}$

$\bf{8x–15x \: ≤ \: −21+20}$

$\bf{−7x \: ≤ \: −1}$

$\bf{−x \: ≤ \: - \frac{1}{7}}$

$\bf{x \: ≥\: \frac{1}{7}}$

$\bf{As  \: x \: ∈ \: R}$

Hence, the solution set is $\bf{x: \: x \: ∈ \: R,x \: ≥ \: \frac{1}{7}}$

So, the correct option is C $\bf{\bigg( \: x: \: x \: ∈ \: R,x \: ≥ \: \frac{1}{7} \bigg)}.$

Representing the solution on a number line:

Answer 2

Answer:

$\huge \green{ \underline{ \underline \green{\bf{Solution:}}}}$

$\bf{Given \: inequation, \: \frac{(4x - 10)}{3} ≤ \: \frac{(5x -7)}{2} }$

$\bf{2(4x - 10) \: ≤ \: 3(5x–7)}$ [On cross-multiplying

$\bf{8x–20 \: ≤ \: 15x–21}$

$\bf{8x–15x \: ≤ \: −21+20}$

$\bf{−7x \: ≤ \: −1}$

$\bf{−x \: ≤ \: - \frac{1}{7}}$

$\bf{x \: ≥\: \frac{1}{7}}$

$\bf{As  \: x \: ∈ \: R}$

Hence, the solution set is $\bf{x: \: x \: ∈ \: R,x \: ≥ \: \frac{1}{7}}$

So, the correct option is C $\bf{\bigg( \: x: \: x \: ∈ \: R,x \: ≥ \: \frac{1}{7} \bigg)}.$

Representing the solution on a number line:[/tex]