Physics, asked by lalani54, 5 months ago

Pls tell all people giving lame answers

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Answered by shuklaabhinav194
0

Answer:

sorry,I can't draw in the graph but

I will answer your second part.

(i)the distance travelled by runner in 5.0 secs

=speed ×time=10m/s×5s

=50 metres Ans(i)

(ii)The distance travelled by car in first 5 secs

=(initial velocity+final velocity)×time/2

=(0+25)5/2

=125/2=62.5 metres Ans(ii)

Plz mark me as brainliest.

Answered by Anonymous
1

Answer:

See the attachment....drawing is not to scale but can give you the idea..

A)

Red lines are for speed of the runner

and blue is for car's speed...

B)

Distance travelled by runner in 5seconds = 50m

Distance travelled by car in 5second=v^2=u^2+2as = 625=10s s=62.5 m

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