Question

pls tell answerr according class 7

Answer 1

Step-by-step explanation:

a−b+2c=0 ………….(1)

a+2b−c=0 ………….(2)

−3a=3b=3c=1

−122−1a=2−111b=11−12c [From equation (1) and (2), by cross-multiplication method]

1−4a=2+1b=2+1c=1

−3a=1

∴a=−3,b=3,c=3.

Answer 2

$a + b + 2c = 0 \: (1)$

$a +2 b - c = 0(2)$

$- 3a = 3b = 3c = 1$

$-112 - 1a = 2-111b = 11 - 12c$ [From equation (1) and (2), by cross-multiplication method]

$1 - 4a = 2 + 1b = 2 + 1c = 1$

$- 3a = 1$

$a = - 3 \: ,b = 3 \: , = 3$