pls ..tell easy method to solve
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Hope this will help you well....
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let the digit at one's place be x
then the digit at ten's place = x+3
the number is = 10×(x+3)+ x
11x+ 30
if digit are interchanged then,
one's place= x+3
ten's place= x
number = 10×x + x+3
=11x + 3
a/q
11x+30 + 11x+3 =143
22x + 33=143
22x= 143-33
22x=110
x=5
therefore original number= 11×5 +30
85;ans.
then the digit at ten's place = x+3
the number is = 10×(x+3)+ x
11x+ 30
if digit are interchanged then,
one's place= x+3
ten's place= x
number = 10×x + x+3
=11x + 3
a/q
11x+30 + 11x+3 =143
22x + 33=143
22x= 143-33
22x=110
x=5
therefore original number= 11×5 +30
85;ans.
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