Question

Pls tell fast plsssssssss

Answer 1

Answer:

do this by taking length of rectangle plus area of two hemispheres

Answer 2

Width of the inner parallel lines =60 m

And the width of the outer lines =40* 2 =80 m

Radius of the inner semicircles=  60/2= 30 m

Radius of the other semicircles =80/2= 40 m

Area of inner rectangle=106*60=6360 m^2

Area of outer rectangle=106*80=8480 m^2

Area of the inner semicircle =

$2*\frac{1}{2} *22/7*30*30=\frac{19800}{7}$

Area of outer semicircles =

$2*\frac{1}{2} *\frac{22}{7} *40*40=\frac{35200}{7}$

Area of racing track = (area of outer rectangle + area of outer semicircles) – (area of inner rectangle + area of inner semicircles)

[8480+(35200/7)]-[6360+(19800/7)]

=13508.57-9188.57

=4320m^2

Mark as the brainliest please ^_^