Question

pls tell guys......​

Answer 1

Answer:

Given system of equations are

| 6x - 2y = 3

6x - 2y - 3 = 0 (1)

kx - y = 2

kx - y - 2 = 0 ----(2)

Compare above equations with

a1x + b1 y + c1 = 0 and

a2 x + b2 y + c2 = 0, we get

a1 = 6, b1 = -2, c1 = -3 ;

a2 = k , b2 = -1, c2 = -2;

Now ,

a1/a2 + b1/b2

[ Given they have Unique solution ]

6/k is not equal(-2 )/( -1)

6/k is not equal2

k/6 not equal 1/2

k is not equal to6/2

k is not equal3

Therefore,

For all real values of k , except k= 3,

Above equations has unique solution.