Question

Pls tell guys...Pls tell the right answer only then i m going to mark u as BRAINLIST...Fasttttt!!!!!!​

Answer 1

Given:

• The figure with the measurements in cm. (Refer to the attachment)

To find:

• Area of the given figure.

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Solution:

We can see that the figure has been divided into three shapes, 2 triangles and 1 rectangle.

Area of both the triangles will be equal, since the measurements are equal.

In order to find the area of a triangle, we need to know its base and height (or perpendicular), but in the figure, the measurement of the height isn't given, so we'll have to find it.

Using $\underline {\mathcal {\red {Pythagoras\ Theorem}}}$

H² = P² + B²

(5)² = P² + (4)²

25 = P² + 16

25 - 16 = P²

9 = P²

$\sf \sqrt{9} = P$

3 cm = P

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Now,

$\boxed {\mathfrak {\green {Area\ of\ triangle = \dfrac {1}{2} \times base \times height}}}$

Area of both the triangles = $\sf \dfrac {4 \times 3}{2} \times 2$

Area of both the triangles = $\sf \dfrac {4 \times 3}{\cancel 2} \times \cancel {2}$

Area of both the triangles = 12cm²

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We know that,

$\boxed {\mathfrak {\pink {Area\ of\ rectangle = length \times breadth}}}$

Here,

• Length = 6 cm
• Breadth = 4+3 = 7 cm

So,

Area of rectangle = 6×7

Area of rectangle = 42 cm²

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Now,

Area of the entire figure = Area of the two triangles + Area of the rectangle

Area of the entire figure = (12+42) cm²

Area of the entire figure = 54 cm²

$\:$

Area:

Area of the entire figure is $\underline {\bf {\purple {54\ cm^{2}}}}$