Math, asked by kena2345, 1 year ago

pls tell how to do this question

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Answered by ria113
3
☺☺ HERE IS YOUR ANSWER ☺☺

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In ∆PQR,

angle QPR + angle PQR + anglePRQ = 180

AnglePQR = angle PRQ ......(PQ = PR)

40 + 2anglePQR = 180

angle PQR = angle PRQ = 70

angle PRT = 20
angle PRT + angle TRQ = 70

angle TRQ = angle TQR = 50. ......(TQ = TR)

In ∆ TRQ,

angle TRQ + angle TQR + angle RTQ = 180

50 + 50 + Angle RTQ = 180

angle RTQ = 80.

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☺ HOPE IT HELPS YOU ☺
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