Question

pls tell......

How to factorise a polynomial of 4 terms without grouping??


Pls dont copy from Google

#60 points
#quality answer needed with example

Answer 1

⚪First polynomial will is variable x

p(x)= ax⁴+bx³+cx²+d



$\huge\boxed{\red{\bf{1st \:method}}}$

Steps are Here :::

▶First find the 2 Zeros by using remainder theorem.

▶ Then suppose 1st zero is $\alpha$
and second zero is $\beta$

▶ And after it here is formula ::

$\alpha + \beta + \gamma + \delta = - \frac{b}{a}:::::::::::: 1(eq) \\ \\ = > \alpha \beta \gamma \delta = - \frac{d}{a}:::::::::::::2(eq)$

Eq= Equation

then u can solved both equation and find the four zeros ..

then factor will.

$(x-\alpha)(x-\beta)(x-\gamma)(x-\delta)$

$\huge\boxed{\bf{2nd \:method}}$

⚫First Find the two zero ${\red{\alpha,\beta}}$

And find it multiplication
${\red{(x-\alpha)(x-\beta)}}$

▶then divide given polynomial by ${\red{\alpha,\beta}}$

after division u will find the quartic polynomial .

factorise it u will find two more zero..

⚫⚫⚫Hope it helps you⚪⚪⚪

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Answer 2

Answer...

✏️FACTORING FOUR OR MORE TERMS BY GROUPING✏️

⚫Break up the polynomial into sets of two. You can go with (x3 + x2) + (–x – 1). ...

⚫Find the GCF of each set and factor it out. The square x2 is the GCF of the first set, and –1 is the GCF of the second set. ...

⚫Factor again as many times as you can. The two terms you've created have a GCF of (x + 1).