Question

Pls tell how to solve this quadratic equation
(1/x+6)+(1/x-10)=(3/x-4)

Answer 1

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$\frac{1}{x + 6} + \frac{1}{x - 10} = \frac{3}{x - 4} \\ \\ = > \frac{x - 10 + x + 6}{(x + 6)(x - 10)} = \frac{3}{x - 4} \\ = > \frac{2x - 4}{ {x}^{2} - 4x - 60 } = \frac{3}{x - 4} \\ = > 3( {x}^{2} - 4x - 60 )= (2x - 4)(x - 4) \\ = > 3 {x}^{2} - 12x - 180 = 2 {x}^{2} - 8x - 4x - 8 \\ = > 3 {x}^{2} - 2 {x}^{2} - 12x + 12x - 180 + 8 = 0 \\ = > {x}^{2} - 172 = 0$

so this is not a quadric equation .

the quadric equation is like

$a {x}^{2} + bx + c = 0$

but here b = 0

so it is not done by quadric equation .

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