Question

pls tell it
find the value of x​

Answer 1

Answer:

3+2x=3 (3-2x)

3+2x=9-6x

2x+6x=9-3

8x=6

x=6/8

x=3/4

hope it will help you kindly mark the answer as brainlist.

Answer 2

Given:

• A linear equation is given to us .
• The linear equation is $\sf{\dfrac{3+2x}{3-2x}=3}$

To Find:

• We have to find the Value of x .

Concept Used:

• We will use transposition method to solve the linear equation.

Answer:

Taking the given equation ,

$\sf{\implies \dfrac{3+2x}{3-2x}=3}$

$\sf{\implies 3+2x =3(3-2x)}$

$\sf{\implies 3+2x = 9-6x}$

$\sf{\implies 2x +6x =9-3}$

$\sf{\implies 8 x=6}$

$\sf{\implies x=\dfrac{6}{8}}$

${\underline{\red{\boxed{\bf{\mapsto x=\dfrac{3}{4}}}}}}$

Verification:

LHS = $\sf{\dfrac{3+2x}{3-2x}}$

=$\sf{\dfrac{3+2\times\dfrac{3}{4}}{3-2\times\dfrac{3}{4}}}$

=$\sf{\dfrac{3+\dfrac{3}{2}}{3-\dfrac{3}{2}}}$

=$\sf{\dfrac{\dfrac{3+6}{2}}{\dfrac{6-3}{2}}}$

=$\sf{\dfrac{9}{3}}$

=$\sf{3}$ =RHS .

Hence verfied.