Question

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Answer 1

Answer:

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Answer 2

Given:

• There is a pole of height of 48m.
• It casts a shadow of length 16√3m.

To Find:

• The angle of elevation of the sun .

Answer:

Given that a pole of height 48m casts a shadow of length 16√3m .

(For figure refer to attachment)

Let us take that angle of elevation of sun is ∅ .

Now in ∆ABC ,

⇒tan∅ = perpendicular/base.

⇒tan∅ = BC/AB .

⇒tan∅ = 48m/16√3m.

⇒tan∅ = 16×√3×√3m / 16√3m .

⇒tan∅ = √3 .

⇒tan∅ = tan60°

On comparing ,

☞ ∅ = 60° .

Hence the angle of elevation of sun was 60°.