Question

pls tell me both urgently​

Answer 1

Answer:

i) <ACD = 110°

ii) x=80° , y= 60° and z= 40°

Step-by-step explanation:

(1) <A + < B = < ACD ( by exterior angle property of triangle)

70° + 40°= <ACD

therefore, <ACD= 110°

2) z + 140°=180°( by linear pair)

z = 40°

now, z + y = 100° (by exterior angle property of triangle)

40° + y = 100°

y = 60°

now, x + y + z = 180°

x +60° + 40°= 180°

x= 180°-100°

x= 80°

Answer 2

Answer:

Answer 1)

Given:-

In ∆ABC,

∠B=40°

∠A=70°

To find:-

m∠ACD=?

Solution:-

∠ACD=∠A+∠B __(Remote Interior angle theorem)

∠ACD=70°+40°

∠ACD=110°

∴∠ACD=110°

∴The measure of ∠ACD is 110°

Answer 2)

Solution:-

∠Z+∠M = 180° __(Angles in linear pair)

∠Z+140°=180°

∠Z =180°-140°

∠Z =40°

∴∠Z =40°

∠y+∠100°=180° __(Angles in linear pair)

∠y =180°-100°

∠y =80°

∴∠y=80°

∠x + ∠y + ∠z =180°__(Angle additional property)

∠x + 80° + 40° =180°

∠x + 120° =180°

∠x =180°-120°

∠x =60°

∴∠x = 60°

∴The measures of x,y,z are 60°,80°,40°

Step-by-step explanation:

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