Question

Pls tell me how to find out limiting reagent in an equation?​

Answer 1

Answer:

Explanation: Limiting reagent is a reaction which is 100% consumed in the chemical reaction

Steps to find LR :

1) First of all balance the chemical equation

2) Convert all the data given of the the reactants into their respective moles

3) Divide the moles of the reactant with respect  to their stoichiometric

co-efficient and the one which has the smallest value among all the reactants is the limiting reagent of the reaction.

Example :

$H_2 + \frac{1}{2} O_2------->H_2O\\\\Taken : 5mole H_2  and 2moleO_2$

Solution:

1 mole $H_2$ reacts with $\frac{1}{2}$ mole of$O_2$. So, 5 mole of $H_2$ requires $\frac{5}{2}$ mole of $O_2$ Here only 2 mole of $O_2$ is present .

So,$O_2$  is limiting reagent in the reaction

Example :$CH_4+O_2---->CO_2+H_2O$\\\\Balancing the eqatiuon\\\$\CH_4+2O_2---->CO_2+2H_2O$\\\\\\BY the steps of finding LR \\ \\CH_4 will be\frac{1}{4}  and  2O_2 will be\frac{2}{2}=1\\ \\\\here \frac{1}{4} is less than 1 \\ \\therefore the moles of CH_4 will be LR

Hope this helps you

Answer 2

to find the real in an equilateral we have to do first that that the mean that want to go and the that for the and the that was and at the wrong if you find to result in the equator what you have that that that the meaning that want to go at that the I don't know the answer sorry I was it