Question

pls tell me on paper or a book and pls Don't sent fltu answer
Solve the equation of x​

Answer 1

Answer:

this is the answer of your question

Step-by-step explanation:

if you like my answer so please tell me.

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\hline\begin{array}{ ||c|| } \small \sf{Used \: law \: of \: exponent}\\ \underline{\underline{ \small \sf \blue{{a}^{m} \div {a}^{n} = {a}^{m - n}}}} \end{array}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mapsto \small\sf \blue{Solution:-}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\blue \mapsto \sf{ \frac{ {5}^{3x} }{5^{ - 4} } \times \frac{25}{ {5}^{x} } = \frac{ {5}^{20} }{5^{12} } }$

$\blue \mapsto \sf{ \frac{ {5}^{3x} }{5^{ - 4} } \times \frac{ {5}^{2} }{ {5}^{x} } = \frac{ {5}^{20} }{5^{12} } }$

$\blue \mapsto \sf{ {5}^{3x \: - \: (- 4)} × 5^{ 2 \: - \: x} } = \frac{ {5}^{20 - 12} }{1} }$

$\blue \mapsto \sf{ \frac{ {5}^{3x \: + \: 4} }{5^{2 \: - \: x} } = \frac{ {5}^{8} }{1} }$

$\blue \mapsto \sf{ \frac{ {5}^{3x + 4- ( 2 - x)} }{1 } = \frac{ {5}^{8} }{1} }$

$\blue \mapsto \sf{ \frac{ {5}^{3x + 4 - 2 + x} }{1 } = \frac{ {5}^{8} }{1} }$

$\blue \mapsto \sf{ \frac{ {5}^{4x \: + \: 2} }{1 } = \frac{ {5}^{8} }{1} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\mapsto \small\sf \blue{Comparing \: both \: sides}$

$\: \: \: \: \: \: \: \: \: \: \: \: \:$

$\blue \mapsto \small\sf{ 4x = 8 - 2}$

$\blue \mapsto \small\sf{ 2x = 6}$

$\blue \mapsto \sf{ x = \cancel\frac{6}{4} }$

$\small \boxed{ \underline{\blue \mapsto \sf{ x = \frac{3}{2} }}}$