Pls Tell me right answer
and get 7 thanks
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Answered by
0
Answer:
ok
Step-by-step explanation:
Let the side BC=a be chosen along x-axis and altitude AD be along y-axis.
AD
2
=AC
2
−DC
2
=a
2
−
4
a
2
=
4
3a
2
∴AD=
2
a
3
Let QPSR be the rectangle inscribed in the triangle.
If A be its area, then A=2xy where (x,y) are the co-ordinates of vertex P which lies on line AC whose equation in intercept form is
a/2
x
+
3a/2
y
=1 or
a
2x
+
a
3
2y
=1⋯(1)
Area A=2xy=x(1−
a
2x
)a
3
...[ from (1) ]
dx
dA
=a
3
(1−
a
4x
)=0
Answered by
3
Answer:
so sorry don't know the answer
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