pls.... tell me the ans
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Hope this helps.
Since PQ is tangent to the left circle at P,
∠QPR = ∠PSR.
Since PQ is tangent to the right circle at Q,
∠PQR = ∠QSR.
So
∠PRQ + ∠PSQ
= ∠PRQ + ∠PSR + ∠QSR
= ∠PRQ + ∠QPR + ∠PQR
= 180° [ angles in a triangle ].
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