Math, asked by dabbu4u2005, 11 months ago

pls tell me the answer....​

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Answered by arpit3719
0

kaun sa ...................


dabbu4u2005: 1 va
Answered by Anonymous
0

Answer:

q1: a=

Step-by-step explanation:

Q3 The condition for passing  three lines  from same point

a1x +b1y+c1 = 0,

a2x+b2y+c2 = 0 and

a3x+b3y+c3=0 is

The determinant

|a1 b1 c1|

|a2 b2 c2|

|a3 b3 c3| = 0

Hence the condition for given lines to be concurrent is

| a b c |

| b c a |

| c a b| = 0

=> a(bc-a²) –b(b²-ca) +r(ab-c²) = 0

=> abc - a³ - b³+abc +abc - c³ = 0

= > -a³-b³-c³ = -3abc

=> a³+b³+c³ = 3abc

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Anonymous: good thanks,your questions are very good
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