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kaun sa ...................
dabbu4u2005:
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Answer:
q1: a=
Step-by-step explanation:
Q3 The condition for passing three lines from same point
a1x +b1y+c1 = 0,
a2x+b2y+c2 = 0 and
a3x+b3y+c3=0 is
The determinant
|a1 b1 c1|
|a2 b2 c2|
|a3 b3 c3| = 0
Hence the condition for given lines to be concurrent is
| a b c |
| b c a |
| c a b| = 0
=> a(bc-a²) –b(b²-ca) +r(ab-c²) = 0
=> abc - a³ - b³+abc +abc - c³ = 0
= > -a³-b³-c³ = -3abc
=> a³+b³+c³ = 3abc
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