Math, asked by Anonymous, 8 months ago

pls tell me the answer​

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Answers

Answered by rani712005
1

Answer:

Step-by-step explanation:

There should be addition sign between (b+c) and (c-a)

See the attachment

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Answered by Lazarus
1

Answer:

(a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a) = 0 (given)

PROOF:-

LHS- (a^2-b^2)+(b^2-c^2)+(c^2-a^2)

a^2-a^2+b^2-b^2+c^2-c^2

=0={LHS =RHS}

HENCE,PROVED.

(Note: Your question in the given pic looks typographical/printing error ,there should be '+' after (b+c))

HOPE THIS HELPS

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