Question

pls tell me the answer​

Answer 1

Step-by-step explanation:

Let O is the center of rhombus.

Then, OC = 12cm

OI = 5cm

We know that, all daigonal bisect at right angle. so, CI =

$= \sqrt{(oc) {}^{2} + {(oi)}^{2} } \\ = \sqrt{ {12}^{2} + {5}^{2} } \\ = \sqrt{144 + 25} \\ = \sqrt{169} \\ = 13 \: cm$

. ' . CI = 13cm

And CI = RI = 13cm ( all side of rhombus is equal)

Similarly,

By pythagoras theoram,

.'. RO =

$= \sqrt{(13) {}^{2} - {(5)}^{2} } \\ = \sqrt{169 - 25} \\ = \sqrt{144} \\ = 12cm$

Thus, x = 12 cm

Similarly,

Y =

$= \sqrt{(rc) {}^{2} - {(or)}^{2} } \\ = \sqrt{ {13 }^{2} - {12}^{2} } \\ = \sqrt{169 - 144} \\ = \sqrt{25} \\ = 5cm$

Hence, x = 12cm, y = 5cm, z = 13cm

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