Question

pls tell me the answer​

Answer 1

Answer:

p(x)=3x

3

+16x

2

+15x−18

x=

3

2

x−

3

2

=0

3

3x−2

=0

⇒3x−2=0

x

2

+6x+9

____________________

3x−2)3x

3

+16x

2

+15x−18

3x

2

−2x

2

(−) (+)

______________________

18x

2

+15x−18

18x

2

−12x

____________________

27x−18

27x−18

________________

0

________________

x

2

+6x+9

x

2

+3x+3x+9

x(x+3)+3(x+3)

(x+3)(x+3)

zeroes

x+3=0 x+3=0

x=−3 x=−3

Zeroes of p(x)=−3,−3,

3

2

Pls mark me Brainlist

Answer 2

Step-by-step explanation:

Given : a cubic polynomial,

one zero is 2/3

If x= 2/3

x-2/3=0

3x-2=0

now divide the given polynomial by this.

3x3+16x2+15x-18÷3x-2

After doing long division method you will get x2+6x+9

now factorise it by middle term splitting

x2+3x+3x+9=0

x(x+3)+3(x+3)=0

(x+3)(x+3)=0

x=-3 and -3

So the other zeroes are -3 and -3.