Question

pls tell me the answer​

Answer 1

Answer:

Prime factorising 2340,

we get,

2340=2×2×3×3×5×13

=2² ×3²×5¹× 13¹

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 2, number of 3's is 2, number of 5's is 1 and number of 13's is 1.

So we need to multiply another 2, 3, 5²and 13²

to the factorization to make 2340 a perfect cube.

Hence, the smallest number by which 2340 must be multiplied to obtain a perfect cube is 2 ×3×5²×13²

=25350.

Answer 2

Answer:Prime factorising 2340,



we get,



2340=2×2×3×3×5×13



=2² ×3²×5¹× 13¹



We know, a perfect cube has multiples of 3 as powers of prime factors.



Here, number of 2's is 2, number of 3's is 2, number of 5's is 1 and number of 13's is 1.



So we need to multiply another 2, 3, 5²and 13²



to the factorization to make 2340 a perfect cube.



Hence, the smallest number by which 2340 must be multiplied to obtain a perfect cube is 2 ×3×5²×13²



=25350.

Step-by-step explanation: