Math, asked by koolinsaan, 1 year ago

pls tell me the answer

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Answered by ramuhema31
0

Answer:


Step-by-step explanation:

Let first no.be x

Second no. be (x+1)

Third no. be(x+2)

Their sum is 40,

Divide each no. By 5,3,4 respectively

X/5+(x+1)/3+(x+2)/4=40

On solving we get ,

Ans .50=x

That means first no.=x=50..

Second no.=(x+1)=50+1=51..

Third no.=(x+2)=50+2=52..

Thus three consecutive no. Are 50,51,52..

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