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length of d=√24^2+10^2 =26cm,r=13
area of shaded region =(πr^2/2) -1/2*26.13
=(π.13.13/2-169)cm^2
=(265.57-169)cm^2
=96.56cm^2
area of shaded region =(πr^2/2) -1/2*26.13
=(π.13.13/2-169)cm^2
=(265.57-169)cm^2
=96.56cm^2
nikhil1000:
plz mark it as brainliest!!!
it is wrong
hey,check it again plz
answer which is given below you is correct
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area of triangle abc=1/2 x10x24=120cm sq.
by pythagoras theorem
ab^2=ac^2+bc^2
ab=√[(24x24)+(10x10)]
ab=√576+100
ab=√676
ab=26cm so radiur=13cm
area of semicirle=1/2xπr^2=1/2xπx(13)^2=π(13)^2/2
area of full cirle=π(13)^2
area of shaded region=(area of full cirle )-(area of semicircle+area of triangle)
=π(13)^2-π(13)^2/2-120
=265.46-120
=145.46cm sq.
by pythagoras theorem
ab^2=ac^2+bc^2
ab=√[(24x24)+(10x10)]
ab=√576+100
ab=√676
ab=26cm so radiur=13cm
area of semicirle=1/2xπr^2=1/2xπx(13)^2=π(13)^2/2
area of full cirle=π(13)^2
area of shaded region=(area of full cirle )-(area of semicircle+area of triangle)
=π(13)^2-π(13)^2/2-120
=265.46-120
=145.46cm sq.
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