Question

Pls tell me the answer for this....​

Answer 1

Answer:

31.75

Step-by-step explanation:

AB=MB−MA=4−2=2cm

AC=MC−MA=6−2=4cm

BD=MD−MB=7−4=3cm

CP=MP−MC=9−6=3cm

DP=MP−MD=9−7=2cm

Area of trapezium=  

1/2  h(a+b), where a and b are parallel sides and h is the height of the trapezium.

Area of triangle= 1/2  bh where b is the base of the triangle and h is the height of the triangle.

Area(MNOPQR)=Area(MNA)+Area(ANOC)+Area(COP)+Area(DQP)+Area(BRQD)+Area(MBR)

⇒Area(MNOPQR)= 1/2 (2×2.5+4×(3+2.5)+3×3+2×2+3×(2+2.5)+4×2.5)

⇒Area(MNOPQR)= 1/2

(5+22+9+4+13.5+10) = 1/2 * 63.5 = 31.75

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