Question

pls tell me the answer of this question

Answer 1

angles of quadrilateral

(3x+15), (x+20), (2x+30), (3x-20)

by angle sum property

sum of all angles of a quadrilateral = 360

(3x+15)+(x+20)+(2x+30)+(3x-20) = 360

9x+45=360

9(x+5)=360

x+5=40

x=35

thus largest angle 3x+15  

=120

smallest angle x+20

=55

their difference= 65

Answer 2

Answer:

Step-by-step explanation:

we know that total measurment of quadrilateral is 360 degree

so, 3x+15+2x+30+x+20+3x-20=

9x+65-20=360

9x+35=360

9x=360-35

9x=325

x=325/9

x=36.11

so, 3x+15= 36.11*3+15=123.33

x+20=36.11+20= 56.11

2x+30=36.11*2+30=102.22

3x-20=36.11*3-20=88.33

greatest angle= 123.33

smallest angle= 56.11

difference= 123.33-56.11

                 =67.22