Physics, asked by pmsmysore2005, 4 hours ago

pls tell me the answer with explanation...​

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Answered by annakashyap
1

Explanation:

Let u be the velocity with which the ball hits the ground, then

u^2=2gh

=2×9.8×10=196

∴u=14m/sec

If v be the velocity with which it rebounds, then

v^2=2×9.8×2.5=49

⇒v=7m/sec

∴Δv=(v−u)

=(7m/sec)−(−14m/sec)

=21m/sec

∴a= Δv/Δt= 21/0.01

=2100m/s^2

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