Pls tell me the answer with the whole process
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given, in triangle ABE ,
AB= 2x+4
AE=3y+8
according to ASA (ANGLE SIDE ANGLE) RULE
triangle ABC ~ ADE (ABC IS congruent TO ADE)
THUS, AB= AE , BC=DE ,AC=AD
( SUBSTITUTE AB , BC ,AE AND DE)
*2x+4=3y+8
y= (2x-4)/3
substitute y in BC=BE
x=2y
x=2×(2x-4)/3
3x=4x-8
4x - 3x = 8
● x=8 ●
SUBSTITUTE x=8 in y=(2x-4)/3
y=[(2×8)-4]/3
y=(16-4)/3
y=12/3
● y=4 ●
therefore, x=8 and y=4
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