pls tell me the answers
Answers
Answer:
answer -6
Step-by-step explanation:
In the first game;
Number of winners= 1
Number of players= 1+3=4
Probability of winning 1/4
In the second game;
Number of winners= 17
Number of players= 17+51= 68
Probability of winning is 17/68
Answer:
We will find the probability of winning in first game and in second game by using the formula of probability number of favourable outcomesnumber of total outcomes
. Next compare the probability of both the games to see which game has better odds of winning. We also have to find the number of winners if the number of losers is 18 in the third game. Let the number of winners be x and equate the ratio of winners to losers of the third game to the first game and find the value of x.
Complete step-by-step answer:
We are given that in the first game there are 1 loser and 3 winners.
That is, we can say out of 4 people only 1 person wins.
As we know probability of an event is given by number of favourable outcomesnumber of total outcomes
Than we can calculate the chance of winning by dividing 1 by 4
Therefore, chance of winning in first game is 14
Similarly in the second game there are 17 winners when there are 51 losers.
That is 17 people will win out of 17+51=68
people
The chances of winning in second game is 1768=14
Thus both the first and second game have the same odds of winning.
Now we want to find the number of winners in the third game if the number of the losers is 18 such that the ratio of winners and losers is the same as that of the first game.
The ratio in the first game of winners to losers is 13
Now let the number of winners be x
Then x18=13
Multiply both sides by 18
x=6
Hence, in the third game there should be 6 winners.