Math, asked by ramsmedicine, 2 months ago

Pls tell me this answers guys

Attachments:

sivasridhar: hope its helpful
sivasridhar: pls mark me as brainaliest !!!

Answers

Answered by sivasridhar
1

___________________________________________

ANSWER :-

___________________________________________

  • First we want to find the area of the given rectangle :

length of given rectangle = 18 cm

breath of given rectangle = 14 cm

so,

  • ⇒ Area of rectangle = l × b

  • ⇒ Area of rectangle = 18 × 14

  • ⇒ Area of rectangle = 252 cm²

Now we want to cut out the area of semi-circle.

  • ⇒ Area of circle = πr²

  •  \sf{Area \: of \: semicircle = \frac{1}{2} \times  \pi \times r \times r  }

  •   \sf{=  \frac{1}{2}  \times  \frac{22}{7}  \times 7 \times 7 =  \frac{1078}{14}  = 77 {cm}^{2} }

SO, The area of given figure is :

  • area of rectangle - semicircle

  • 252 - 77

  • = 175 cm²

___________________________________________

∴ The area of the given figure

is 175 cm²

___________________________________________

IMPORTANT FORMULAS :-

___________________________________________

❥ SQUARE :-

Area of square = a²

Perimeter of square = 4a

❥ RECTANGLE :-

Area of rectangle = l × b

Perimeter of rectangle = 2(l+b)

❥ TRIANGLE :-

Area of triangle = ½b×h

Perimeter of triangle = a+b+c

❥ PARALLELOGRAM :-

Area of parallelogram = h × b

Perimeter of parallelogram = 2(a+b)

❥ CIRCLE :-

Area of circle = πr²

Perimeter of circle = 2 πr

❥ ROMBUS :-

Area of rombus = ½d¹d²

Perimeter of rombus = 4a

❥ TRAPIEZUIM :-

Area of trapezuim = h × a+b/2

Perimeter of trapezuim = a+b+c+d

❥ QUADRILATERAL :-

Area of quadrilateral = ½d(h¹+h²)

___________________________________________

Similar questions