Question

pls tell me this table​

Answer 1

Answer:

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Answer 2

a)Acceleration=Change in Velocity/Time

                        =65-60=5

                         =10 min=1/6 h

                         = 5/1*6=30km/h²

b) Si unit of speed=m/s

=Speed at 10:45 p.m.= 90km/h

                                   =90×1000/60=25 m/s

c)10:25 p.m. to 10:35 p.m= 74-62=12

  10:35 p.m. to 10:45 p.m.= 90-74=16

   10:45 p.m. to 10:55 p.m.= 90-65=30

10:55 p.m. to 11:05 p.m. =65-60=5

11:05 p.m. to 11:15 p.m. = 65-38=27

Therefore speed at 10:45 p.m. to 10:55 p.m. has the highest change.

d)t=10min=1/6 h

  u=65km/h

  v=38 km/h

  a=u-v/t

 a= 38-65/1/6=-162km/h²

S=v²-u²/2a

S=38²-65²/2×(-162)=8.58km

Hope it helps.